Evaluate (3n^3+2n-7)-(n^3-n-2)

$(3 n^{3} + 2 n - 7) - (n^{3} - n - 2)$

Step 1

Simplify each term.

Apply the distributive property.

$3 n^{3} + 2 n - 7 - n^{3} - - n - - 2$

Simplify.

Multiply $- - n$ .

Multiply $- 1$ by $- 1$ .

$3 n^{3} + 2 n - 7 - n^{3} + 1 n - - 2$

Multiply $n$ by $1$ .

$3 n^{3} + 2 n - 7 - n^{3} + n - - 2$

$3 n^{3} + 2 n - 7 - n^{3} + n - - 2$

Multiply $- 1$ by $- 2$ .

$3 n^{3} + 2 n - 7 - n^{3} + n + 2$

$3 n^{3} + 2 n - 7 - n^{3} + n + 2$

$3 n^{3} + 2 n - 7 - n^{3} + n + 2$

Step 2

Simplify by adding terms.

Subtract $n^{3}$ from $3 n^{3}$ .

$2 n^{3} + 2 n - 7 + n + 2$

Add $2 n$ and $n$ .

$2 n^{3} + 3 n - 7 + 2$

Add $- 7$ and $2$ .

$2 n^{3} + 3 n - 5$

$2 n^{3} + 3 n - 5$

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