Evaluate (4^2)÷((2^3)÷((-1)*(9+(-5))))

$4^{2} \div (2^{3} \div ((- 1) \cdot (9 + (- 5))))$

Step 1

To divide by a fraction, multiply by its reciprocal.

$4^{2} \frac{- 1 \cdot (9 - 5)}{2^{3}}$

Step 2

Raise $4$ to the power of $2$ .

$16 \frac{- 1 \cdot (9 - 5)}{2^{3}}$

Step 3

Subtract $5$ from $9$ .

$16 \frac{- 1 \cdot 4}{2^{3}}$

Step 4

Reduce the expression by cancelling the common factors.

Raise $2$ to the power of $3$ .

$16 \frac{- 1 \cdot 4}{8}$

Multiply $- 1$ by $4$ .

$16 (\frac{- 4}{8})$

Cancel the common factor of $8$ .

Factor $8$ out of $16$ .

$8 (2) \frac{- 4}{8}$

Cancel the common factor.

$8 \cdot 2 \frac{- 4}{8}$

Rewrite the expression.

$2 \cdot - 4$

Multiply $2$ by $- 4$ .

$- 8$