Evaluate (4+9)-(3(6))/2+8

$(4 + 9) - \frac{3 (6)}{2} + 8$

Step 1

Find the common denominator.

Write $4$ as a fraction with denominator $1$ .

$\frac{4}{1} + 9 - \frac{3 (6)}{2} + 8$

Multiply $\frac{4}{1}$ by $\frac{2}{2}$ .

$\frac{4}{1} \cdot \frac{2}{2} + 9 - \frac{3 (6)}{2} + 8$

Multiply $\frac{4}{1}$ by $\frac{2}{2}$ .

$\frac{4 \cdot 2}{2} + 9 - \frac{3 (6)}{2} + 8$

Write $9$ as a fraction with denominator $1$ .

$\frac{4 \cdot 2}{2} + \frac{9}{1} - \frac{3 (6)}{2} + 8$

Multiply $\frac{9}{1}$ by $\frac{2}{2}$ .

$\frac{4 \cdot 2}{2} + \frac{9}{1} \cdot \frac{2}{2} - \frac{3 (6)}{2} + 8$

Multiply $\frac{9}{1}$ by $\frac{2}{2}$ .

$\frac{4 \cdot 2}{2} + \frac{9 \cdot 2}{2} - \frac{3 (6)}{2} + 8$

Write $8$ as a fraction with denominator $1$ .

$\frac{4 \cdot 2}{2} + \frac{9 \cdot 2}{2} - \frac{3 (6)}{2} + \frac{8}{1}$

Multiply $\frac{8}{1}$ by $\frac{2}{2}$ .

$\frac{4 \cdot 2}{2} + \frac{9 \cdot 2}{2} - \frac{3 (6)}{2} + \frac{8}{1} \cdot \frac{2}{2}$

Multiply $\frac{8}{1}$ by $\frac{2}{2}$ .

$\frac{4 \cdot 2}{2} + \frac{9 \cdot 2}{2} - \frac{3 (6)}{2} + \frac{8 \cdot 2}{2}$

Step 2

Combine the numerators over the common denominator.

$\frac{4 \cdot 2 + 9 \cdot 2 - 3 \cdot 6 + 8 \cdot 2}{2}$

Step 3

Simplify each term.

Multiply $4$ by $2$ .

$\frac{8 + 9 \cdot 2 - 3 \cdot 6 + 8 \cdot 2}{2}$

Multiply $9$ by $2$ .

$\frac{8 + 18 - 3 \cdot 6 + 8 \cdot 2}{2}$

Multiply $- 3$ by $6$ .

$\frac{8 + 18 - 18 + 8 \cdot 2}{2}$

Multiply $8$ by $2$ .

$\frac{8 + 18 - 18 + 16}{2}$

Step 4

Simplify the expression.

Add $8$ and $18$ .

$\frac{26 - 18 + 16}{2}$

Subtract $18$ from $26$ .

$\frac{8 + 16}{2}$

Add $8$ and $16$ .

$\frac{24}{2}$

Divide $24$ by $2$ .

$12$