Evaluate 5^0+4^1+(-1)^2+(-2)^3

$5^{0} + 4^{1} + {(- 1)}^{2} + {(- 2)}^{3}$

Simplify each term.

Anything raised to $0$ is $1$ .

$1 + 4^{1} + {(- 1)}^{2} + {(- 2)}^{3}$

Evaluate the exponent.

$1 + 4 + {(- 1)}^{2} + {(- 2)}^{3}$

Raise $- 1$ to the power of $2$ .

$1 + 4 + 1 + {(- 2)}^{3}$

Raise $- 2$ to the power of $3$ .

$1 + 4 + 1 - 8$

$1 + 4 + 1 - 8$

Simplify by adding and subtracting.

Add $1$ and $4$ .

$5 + 1 - 8$

Add $5$ and $1$ .

$6 - 8$

Subtract $8$ from $6$ .

$- 2$

$- 2$

Related Questions