Evaluate (5-1/55)^2(6/3)-(7)-31/5*5

${(5 - \frac{1}{5} \cdot 5)}^{2} (\frac{6}{3}) - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Step 1

Simplify each term.

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{1}{5}$ into the numerator.

${(5 + \frac{- 1}{5} \cdot 5)}^{2} \frac{6}{3} - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Cancel the common factor.

${(5 + \frac{- 1}{5} \cdot 5)}^{2} \frac{6}{3} - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Rewrite the expression.

${(5 - 1)}^{2} \frac{6}{3} - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Subtract $1$ from $5$ .

$4^{2} \frac{6}{3} - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Raise $4$ to the power of $2$ .

$16 (\frac{6}{3}) - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Divide $6$ by $3$ .

$16 \cdot 2 - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Multiply $16$ by $2$ .

$32 - (7) - 3 \cdot \frac{1}{5} \cdot 5$

Multiply $- 1$ by $7$ .

$32 - 7 - 3 \cdot \frac{1}{5} \cdot 5$

Combine $- 3$ and $\frac{1}{5}$ .

$32 - 7 + \frac{- 3}{5} \cdot 5$

Cancel the common factor of $5$ .

Cancel the common factor.

$32 - 7 + \frac{- 3}{5} \cdot 5$

Rewrite the expression.

$32 - 7 - 3$

Step 2

Simplify by subtracting numbers.

Subtract $7$ from $32$ .

$25 - 3$

Subtract $3$ from $25$ .

$22$

Evaluate (5-1/5*5)^2(6/3)-(7)-3*1/5*5