Evaluate (5^2-3^4)/((2^3-5)*((6^2)÷9))

$\frac{5^{2} - 3^{4}}{(2^{3} - 5) \cdot (6^{2} \div 9)}$

Raise $6$ to the power of $2$ .

$\frac{5^{2} - 3^{4}}{(2^{3} - 5) \cdot 36 \div 9}$

Simplify the numerator.

Raise $5$ to the power of $2$ .

$\frac{25 - 3^{4}}{(2^{3} - 5) \cdot 36 \div 9}$

Raise $3$ to the power of $4$ .

$\frac{25 - 1 \cdot 81}{(2^{3} - 5) \cdot 36 \div 9}$

Multiply $- 1$ by $81$ .

$\frac{25 - 81}{(2^{3} - 5) \cdot 36 \div 9}$

Subtract $81$ from $25$ .

$\frac{- 56}{(2^{3} - 5) \cdot 36 \div 9}$

Simplify the denominator.

Raise $2$ to the power of $3$ .

$\frac{- 56}{(8 - 5) 36 \div 9}$

Subtract $5$ from $8$ .

$\frac{- 56}{3 (36 \div 9)}$

Divide $36$ by $9$ .

$\frac{- 56}{3 \cdot 4}$

Reduce the expression by cancelling the common factors.

Multiply $3$ by $4$ .

$\frac{- 56}{12}$

Cancel the common factor of $- 56$ and $12$ .

Factor $4$ out of $- 56$ .

$\frac{4 (- 14)}{12}$

Cancel the common factors.

Factor $4$ out of $12$ .

$\frac{4 \cdot - 14}{4 \cdot 3}$

Cancel the common factor.

$\frac{4 \cdot - 14}{4 \cdot 3}$

Rewrite the expression.

$\frac{- 14}{3}$

Move the negative in front of the fraction.

$- \frac{14}{3}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{14}{3}$

Decimal Form:

$- 4.\overline{6}$

Mixed Number Form:

$- 4 \frac{2}{3}$