Evaluate (5-4)/(4^-3)

$\frac{5 - 4}{4^{- 3}}$

Move $4^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$(5 - 4) \cdot 4^{3}$

Subtract $4$ from $5$ .

$1 \cdot 4^{3}$

Multiply $4^{3}$ by $1$ .

$4^{3}$

Raise $4$ to the power of $3$ .

$64$