Evaluate 5^( log base 5 of 3)- natural log of e^4+e^0

$5^{\log_{5} (3)} - \ln (e^{4}) + e^{0}$

Simplify each term.

Exponentiation and log are inverse functions.

$3 - \ln (e^{4}) + e^{0}$

Use logarithm rules to move $4$ out of the exponent.

$3 - (4 \ln (e)) + e^{0}$

The natural logarithm of $e$ is $1$ .

$3 - (4 \cdot 1) + e^{0}$

Multiply $4$ by $1$ .

$3 - 1 \cdot 4 + e^{0}$

Multiply $- 1$ by $4$ .

$3 - 4 + e^{0}$

Anything raised to $0$ is $1$ .

$3 - 4 + 1$

Simplify by adding and subtracting.

Subtract $4$ from $3$ .

$- 1 + 1$

Add $- 1$ and $1$ .

$0$