Evaluate 5cos(4/2)^2+ natural log of 4+1-3

$5 \cos^{2} (\frac{4}{2}) + \ln (4 + 1) - 3$

Divide $4$ by $2$ .

$5 \cos^{2} (2) + \ln (4 + 1) - 3$

Add $4$ and $1$ .

$5 \cos^{2} (2) + \ln (5) - 3$

The result can be shown in multiple forms.

Exact Form:

$5 \cos^{2} (2) + \ln (5) - 3$

Decimal Form:

$3.60334803 \dots$