Evaluate (-5x^-3y^0)^-1

${(- 5 x^{- 3} y^{0})}^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

${(- 5 \frac{1}{x^{3}} y^{0})}^{- 1}$

Combine $- 5$ and $\frac{1}{x^{3}}$ .

${(\frac{- 5}{x^{3}} y^{0})}^{- 1}$

Simplify the expression.

Move the negative in front of the fraction.

${(- \frac{5}{x^{3}} y^{0})}^{- 1}$

Anything raised to $0$ is $1$ .

${(- \frac{5}{x^{3}} \cdot 1)}^{- 1}$

Multiply $- 1$ by $1$ .

${(- \frac{5}{x^{3}})}^{- 1}$

Change the sign of the exponent by rewriting the base as its reciprocal.

$- \frac{x^{3}}{5}$