Evaluate 6*(4+2)^2-3^2

$6 \cdot {(4 + 2)}^{2} - 3^{2}$

Step 1

Simplify each term.

Add $4$ and $2$ .

$6 \cdot 6^{2} - 3^{2}$

Multiply $6$ by $6^{2}$ by adding the exponents.

Multiply $6$ by $6^{2}$ .

Raise $6$ to the power of $1$ .

$6^{1} \cdot 6^{2} - 3^{2}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$6^{1 + 2} - 3^{2}$

Add $1$ and $2$ .

$6^{3} - 3^{2}$

Raise $6$ to the power of $3$ .

$216 - 3^{2}$

Raise $3$ to the power of $2$ .

$216 - 1 \cdot 9$

Multiply $- 1$ by $9$ .

$216 - 9$

Step 2

Subtract $9$ from $216$ .

$207$