Evaluate 6(-4)(-5/6)(-3/4)

$6 (- 4) (- \frac{5}{6}) (- \frac{3}{4})$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$6 (- 4) (- \frac{5}{6}) \cdot \frac{- 3}{4}$

Factor $2$ out of $6 (- 4) (- \frac{5}{6})$ .

$2 (3 \cdot - 4 (- \frac{5}{6})) \cdot \frac{- 3}{4}$

Factor $2$ out of $4$ .

$2 (3 \cdot - 4 (- \frac{5}{6})) \cdot \frac{- 3}{2 (2)}$

Cancel the common factor.

$2 (3 \cdot - 4 (- \frac{5}{6})) \cdot \frac{- 3}{2 \cdot 2}$

Rewrite the expression.

$3 \cdot - 4 (- \frac{5}{6}) \cdot \frac{- 3}{2}$

Multiply.

Multiply $3$ by $- 4$ .

$- 12 (- \frac{5}{6}) \cdot \frac{- 3}{2}$

Multiply $- 1$ by $- 12$ .

$12 (\frac{5}{6}) \cdot \frac{- 3}{2}$

Combine $12$ and $\frac{5}{6}$ .

$\frac{12 \cdot 5}{6} \cdot \frac{- 3}{2}$

Multiply $12$ by $5$ .

$\frac{60}{6} \cdot \frac{- 3}{2}$

Multiply $\frac{60}{6}$ by $\frac{- 3}{2}$ .

$\frac{60 \cdot - 3}{6 \cdot 2}$

Simplify the expression.

Multiply $60$ by $- 3$ .

$\frac{- 180}{6 \cdot 2}$

Multiply $6$ by $2$ .

$\frac{- 180}{12}$

Divide $- 180$ by $12$ .

$- 15$