Evaluate 64+3^3-4(6-2)^2

$64 + 3^{3} - 4 {(6 - 2)}^{2}$

Step 1

Simplify each term.

Raise $3$ to the power of $3$ .

$64 + 27 - 4 {(6 - 2)}^{2}$

Subtract $2$ from $6$ .

$64 + 27 - 4 \cdot 4^{2}$

Raise $4$ to the power of $2$ .

$64 + 27 - 4 \cdot 16$

Multiply $- 4$ by $16$ .

$64 + 27 - 64$

$64 + 27 - 64$

Step 2

Simplify by adding and subtracting.

Add $64$ and $27$ .

$91 - 64$

Subtract $64$ from $91$ .

$27$

$27$

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