Evaluate (-6x+3)-(-2x^2+6x-10)

$(- 6 x + 3) - (- 2 x^{2} + 6 x - 10)$

Step 1

Simplify each term.

Apply the distributive property.

$- 6 x + 3 - (- 2 x^{2}) - (6 x) - - 10$

Simplify.

Multiply $- 2$ by $- 1$ .

$- 6 x + 3 + 2 x^{2} - (6 x) - - 10$

Multiply $6$ by $- 1$ .

$- 6 x + 3 + 2 x^{2} - 6 x - - 10$

Multiply $- 1$ by $- 10$ .

$- 6 x + 3 + 2 x^{2} - 6 x + 10$

$- 6 x + 3 + 2 x^{2} - 6 x + 10$

$- 6 x + 3 + 2 x^{2} - 6 x + 10$

Step 2

Simplify by adding terms.

Subtract $6 x$ from $- 6 x$ .

$- 12 x + 3 + 2 x^{2} + 10$

Add $3$ and $10$ .

$- 12 x + 2 x^{2} + 13$

$- 12 x + 2 x^{2} + 13$

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