Evaluate ((7-2)^2)/(5^1)-3*-3

$\frac{{(7 - 2)}^{2}}{5^{1}} - 3 \cdot - 3$

Subtract $2$ from $7$ .

$\frac{5^{2}}{5^{1}} - 3 \cdot - 3$

Simplify each term.

Cancel the common factor of $5^{2}$ and $5^{1}$ .

Factor $5$ out of $5^{2}$ .

$\frac{5 \cdot 5}{5^{1}} - 3 \cdot - 3$

Cancel the common factors.

Factor $5$ out of $5^{1}$ .

$\frac{5 \cdot 5}{5 \cdot 1} - 3 \cdot - 3$

Cancel the common factor.

$\frac{5 \cdot 5}{5 \cdot 1} - 3 \cdot - 3$

Rewrite the expression.

$\frac{5}{1} - 3 \cdot - 3$

Divide $5$ by $1$ .

$5 - 3 \cdot - 3$

$5 - 3 \cdot - 3$

$5 - 3 \cdot - 3$

Multiply $- 3$ by $- 3$ .

$5 + 9$

$5 + 9$

Add $5$ and $9$ .

$14$

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