Evaluate 7^2-|6-27|3^2

$7^{2} - | 6 - 2 \cdot 7 | \cdot 3^{2}$

Step 1

Simplify each term.

Raise $7$ to the power of $2$ .

$49 - | 6 - 2 \cdot 7 | \cdot 3^{2}$

Multiply $- 2$ by $7$ .

$49 - | 6 - 14 | \cdot 3^{2}$

Subtract $14$ from $6$ .

$49 - | - 8 | \cdot 3^{2}$

The absolute value is the distance between a number and zero. The distance between $- 8$ and $0$ is $8$ .

$49 - 1 \cdot 8 \cdot 3^{2}$

Multiply $- 1$ by $8$ .

$49 - 8 \cdot 3^{2}$

Raise $3$ to the power of $2$ .

$49 - 8 \cdot 9$

Multiply $- 8$ by $9$ .

$49 - 72$

Step 2

Subtract $72$ from $49$ .

$- 23$

Evaluate 7^2-|6-2*7|*3^2