Evaluate (7-3)* square root of 25*2-10

$(7 - 3) \cdot \sqrt{25} \cdot 2 - 10$

Simplify each term.

Subtract $3$ from $7$ .

$4 \cdot \sqrt{25} \cdot 2 - 10$

Rewrite $25$ as $5^{2}$ .

$4 \cdot \sqrt{5^{2}} \cdot 2 - 10$

Pull terms out from under the radical, assuming positive real numbers.

$4 \cdot 5 \cdot 2 - 10$

Multiply $4$ by $5$ .

$20 \cdot 2 - 10$

Multiply $20$ by $2$ .

$40 - 10$

Subtract $10$ from $40$ .

$30$