Evaluate 7/( square root of 12x)

$\frac{7}{\sqrt{12 x}}$

Step 1

Simplify the denominator.

Rewrite $12 x$ as $2^{2} \cdot (3 x)$ .

Factor $4$ out of $12$ .

$\frac{7}{\sqrt{4 (3) x}}$

Rewrite $4$ as $2^{2}$ .

$\frac{7}{\sqrt{2^{2} \cdot 3 x}}$

Add parentheses.

$\frac{7}{\sqrt{2^{2} \cdot (3 x)}}$

Pull terms out from under the radical.

$\frac{7}{2 \sqrt{3 x}}$

Step 2

Multiply $\frac{7}{2 \sqrt{3 x}}$ by $\frac{\sqrt{3 x}}{\sqrt{3 x}}$ .

$\frac{7}{2 \sqrt{3 x}} \cdot \frac{\sqrt{3 x}}{\sqrt{3 x}}$

Step 3

Combine and simplify the denominator.

Multiply $\frac{7}{2 \sqrt{3 x}}$ by $\frac{\sqrt{3 x}}{\sqrt{3 x}}$ .

$\frac{7 \sqrt{3 x}}{2 \sqrt{3 x} \sqrt{3 x}}$

Move $\sqrt{3 x}$ .

$\frac{7 \sqrt{3 x}}{2 (\sqrt{3 x} \sqrt{3 x})}$

Raise $\sqrt{3 x}$ to the power of $1$ .

$\frac{7 \sqrt{3 x}}{2 ({\sqrt{3 x}}^{1} \sqrt{3 x})}$

Raise $\sqrt{3 x}$ to the power of $1$ .

$\frac{7 \sqrt{3 x}}{2 ({\sqrt{3 x}}^{1} {\sqrt{3 x}}^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{7 \sqrt{3 x}}{2 {\sqrt{3 x}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{7 \sqrt{3 x}}{2 {\sqrt{3 x}}^{2}}$

Rewrite ${\sqrt{3 x}}^{2}$ as $3 x$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3 x}$ as ${(3 x)}^{\frac{1}{2}}$ .

$\frac{7 \sqrt{3 x}}{2 {({(3 x)}^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{7 \sqrt{3 x}}{2 {(3 x)}^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{7 \sqrt{3 x}}{2 {(3 x)}^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{7 \sqrt{3 x}}{2 {(3 x)}^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{7 \sqrt{3 x}}{2 {(3 x)}^{1}}$

Simplify.

$\frac{7 \sqrt{3 x}}{2 (3 x)}$

Step 4

Multiply $2$ by $3$ .

$\frac{7 \sqrt{3 x}}{6 x}$

Evaluate 7/( square root of 12x)

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