Evaluate 729^(-4/3)

$729^{- \frac{4}{3}}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{729^{\frac{4}{3}}}$

Step 2

Simplify the denominator.

Rewrite $729$ as $9^{3}$ .

$\frac{1}{{(9^{3})}^{\frac{4}{3}}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{9^{3 (\frac{4}{3})}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{1}{9^{3 (\frac{4}{3})}}$

Rewrite the expression.

$\frac{1}{9^{4}}$

Raise $9$ to the power of $4$ .

$\frac{1}{6561}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{6561}$

Decimal Form:

$0.00015241 \dots$