Evaluate (8-2)^2+1/4(4-3(6-10))

${(8 - 2)}^{2} + \frac{1}{4} (4 - 3 (6 - 10))$

Simplify each term.

Subtract $2$ from $8$ .

$6^{2} + \frac{1}{4} \cdot (4 - 3 (6 - 10))$

Raise $6$ to the power of $2$ .

$36 + \frac{1}{4} \cdot (4 - 3 (6 - 10))$

Simplify each term.

Subtract $10$ from $6$ .

$36 + \frac{1}{4} \cdot (4 - 3 \cdot - 4)$

Multiply $- 3$ by $- 4$ .

$36 + \frac{1}{4} \cdot (4 + 12)$

$36 + \frac{1}{4} \cdot (4 + 12)$

Add $4$ and $12$ .

$36 + \frac{1}{4} \cdot 16$

Cancel the common factor of $4$ .

Factor $4$ out of $16$ .

$36 + \frac{1}{4} \cdot (4 (4))$

Cancel the common factor.

$36 + \frac{1}{4} \cdot (4 \cdot 4)$

Rewrite the expression.

$36 + 4$

$36 + 4$

$36 + 4$

Add $36$ and $4$ .

$40$

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