Evaluate 8+2(x-6)=-2+2x-2

$8 + 2 (x - 6) = - 2 + 2 x - 2$

Step 1

Simplify $8 + 2 (x - 6)$ .

Simplify each term.

Apply the distributive property.

$8 + 2 x + 2 \cdot - 6 = - 2 + 2 x - 2$

Multiply $2$ by $- 6$ .

$8 + 2 x - 12 = - 2 + 2 x - 2$

Subtract $12$ from $8$ .

$2 x - 4 = - 2 + 2 x - 2$

Step 2

Subtract $2$ from $- 2$ .

$2 x - 4 = 2 x - 4$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$2 x - 4 - 2 x = - 4$

Combine the opposite terms in $2 x - 4 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$0 - 4 = - 4$

Subtract $4$ from $0$ .

$- 4 = - 4$

Step 4

Since $- 4 = - 4$ , the equation will always be true.

Always true

Step 5

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$