Evaluate 8+(3^2*(25-5))÷4+3

$8 + 3^{2} \cdot (25 - 5) \div 4 + 3$

Step 1

Subtract $5$ from $25$ .

$8 + 3^{2} \cdot 20 \div 4 + 3$

Step 2

Find the common denominator.

Write $8$ as a fraction with denominator $1$ .

$\frac{8}{1} + 3^{2} \cdot 20 \div 4 + 3$

Multiply $\frac{8}{1}$ by $\frac{4}{4}$ .

$\frac{8}{1} \cdot \frac{4}{4} + 3^{2} \cdot 20 \div 4 + 3$

Multiply $\frac{8}{1}$ by $\frac{4}{4}$ .

$\frac{8 \cdot 4}{4} + 3^{2} \cdot 20 \div 4 + 3$

Write $3$ as a fraction with denominator $1$ .

$\frac{8 \cdot 4}{4} + 3^{2} \cdot 20 \div 4 + \frac{3}{1}$

Multiply $\frac{3}{1}$ by $\frac{4}{4}$ .

$\frac{8 \cdot 4}{4} + 3^{2} \cdot 20 \div 4 + \frac{3}{1} \cdot \frac{4}{4}$

Multiply $\frac{3}{1}$ by $\frac{4}{4}$ .

$\frac{8 \cdot 4}{4} + 3^{2} \cdot 20 \div 4 + \frac{3 \cdot 4}{4}$

Step 3

Combine the numerators over the common denominator.

$\frac{8 \cdot 4 + 3^{2} \cdot 20 + 3 \cdot 4}{4}$

Step 4

Simplify each term.

Multiply $8$ by $4$ .

$\frac{32 + 3^{2} \cdot 20 + 3 \cdot 4}{4}$

Raise $3$ to the power of $2$ .

$\frac{32 + 9 \cdot 20 + 3 \cdot 4}{4}$

Multiply $9$ by $20$ .

$\frac{32 + 180 + 3 \cdot 4}{4}$

Multiply $3$ by $4$ .

$\frac{32 + 180 + 12}{4}$

Step 5

Simplify the expression.

Add $32$ and $180$ .

$\frac{212 + 12}{4}$

Add $212$ and $12$ .

$\frac{224}{4}$

Divide $224$ by $4$ .

$56$