Evaluate (8/4)^2-16/(8-4)

${(\frac{8}{4})}^{2} - \frac{16}{8 - 4}$

Step 1

Simplify each term.

Divide $8$ by $4$ .

$2^{2} - \frac{16}{8 - 4}$

Raise $2$ to the power of $2$ .

$4 - \frac{16}{8 - 4}$

Cancel the common factor of $16$ and $8 - 4$ .

Factor $4$ out of $16$ .

$4 - \frac{4 (4)}{8 - 4}$

Cancel the common factors.

Factor $4$ out of $8$ .

$4 - \frac{4 \cdot 4}{4 \cdot 2 - 4}$

Factor $4$ out of $- 4$ .

$4 - \frac{4 (4)}{4 \cdot 2 + 4 \cdot - 1}$

Factor $4$ out of $4 \cdot 2 + 4 \cdot - 1$ .

$4 - \frac{4 (4)}{4 \cdot (2 - 1)}$

Cancel the common factor.

$4 - \frac{4 \cdot 4}{4 \cdot (2 - 1)}$

Rewrite the expression.

$4 - \frac{4}{2 - 1}$

$4 - \frac{4}{2 - 1}$

$4 - \frac{4}{2 - 1}$

Subtract $1$ from $2$ .

$4 - \frac{4}{1}$

Divide $4$ by $1$ .

$4 - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$4 - 4$

$4 - 4$

Step 2

Subtract $4$ from $4$ .

$0$

Related Questions