Evaluate (8/4)^3-3^2

${(\frac{8}{4})}^{3} - 3^{2}$

Simplify each term.

Divide $8$ by $4$ .

$2^{3} - 3^{2}$

Raise $2$ to the power of $3$ .

$8 - 3^{2}$

Raise $3$ to the power of $2$ .

$8 - 1 \cdot 9$

Multiply $- 1$ by $9$ .

$8 - 9$

$8 - 9$

Subtract $9$ from $8$ .

$- 1$

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