Evaluate -|-9-10|+(12^2)÷6*3

$- | - 9 - 10 | + 12^{2} \div 6 \cdot 3$

Step 1

Simplify each term.

Subtract $10$ from $- 9$ .

$- | - 19 | + 12^{2} \div 6 \cdot 3$

The absolute value is the distance between a number and zero. The distance between $- 19$ and $0$ is $19$ .

$- 1 \cdot 19 + 12^{2} \div 6 \cdot 3$

Multiply $- 1$ by $19$ .

$- 19 + 12^{2} \div 6 \cdot 3$

Raise $12$ to the power of $2$ .

$- 19 + 144 \div 6 \cdot 3$

Divide $144$ by $6$ .

$- 19 + 24 \cdot 3$

Multiply $24$ by $3$ .

$- 19 + 72$

Step 2

Add $- 19$ and $72$ .

$53$