Evaluate (9-7)^3+4^2*2

${(9 - 7)}^{3} + 4^{2} \cdot 2$

Simplify each term.

Subtract $7$ from $9$ .

$2^{3} + 4^{2} \cdot 2$

Raise $2$ to the power of $3$ .

$8 + 4^{2} \cdot 2$

Raise $4$ to the power of $2$ .

$8 + 16 \cdot 2$

Multiply $16$ by $2$ .

$8 + 32$

$8 + 32$

Add $8$ and $32$ .

$40$

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