Evaluate cos(theta)=5/8

$\cos (θ) = \frac{5}{8}$

Take the inverse cosine of both sides of the equation to extract $θ$ from inside the cosine.

$θ = \arccos (\frac{5}{8})$

Simplify the right side.

Evaluate $\arccos (\frac{5}{8})$ .

$θ = 0.89566479$

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$θ = 2 (3.14159265) - 0.89566479$

Solve for $θ$ .

Remove parentheses.

$θ = 2 (3.14159265) - 0.89566479$

Simplify $2 (3.14159265) - 0.89566479$ .

Multiply $2$ by $3.14159265$ .

$θ = 6.2831853 - 0.89566479$

Subtract $0.89566479$ from $6.2831853$ .

$θ = 5.38752051$

Find the period of $\cos (θ)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

The period of the $\cos (θ)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$θ = 0.89566479 + 2 π n, 5.38752051 + 2 π n$ , for any integer $n$

The result can be shown in multiple forms.

Exact Form:

$\cos (θ) = \frac{5}{8}$

Decimal Form:

$\cos (θ) = 0.625$

Evaluate cos(theta)=5/8

Related Questions

Support LCMGCF.com by disabling your adblocker.