Evaluate ( cube root of 128)/( cube root of 2)

$\frac{\sqrt[3]{128}}{\sqrt[3]{2}}$

Step 1

Combine $\sqrt[3]{128}$ and $\sqrt[3]{2}$ into a single radical.

$\sqrt[3]{\frac{128}{2}}$

Step 2

Simplify the expression.

Divide $128$ by $2$ .

$\sqrt[3]{64}$

Rewrite $64$ as $4^{3}$ .

$\sqrt[3]{4^{3}}$

Pull terms out from under the radical, assuming real numbers.

$4$