Evaluate cube root of 16* cube root of 4

$\sqrt[3]{16} \cdot \sqrt[3]{4}$

Step 1

Combine using the product rule for radicals.

$\sqrt[3]{16 \cdot 4}$

Step 2

Simplify the expression.

Multiply $16$ by $4$ .

$\sqrt[3]{64}$

Rewrite $64$ as $4^{3}$ .

$\sqrt[3]{4^{3}}$

Pull terms out from under the radical, assuming real numbers.

$4$