Evaluate cube root of 3 cube root of 243

$\sqrt[3]{3} \sqrt[3]{243}$

Step 1

Combine using the product rule for radicals.

$\sqrt[3]{3 \cdot 243}$

Step 2

Simplify the expression.

Multiply $3$ by $243$ .

$\sqrt[3]{729}$

Rewrite $729$ as $9^{3}$ .

$\sqrt[3]{9^{3}}$

Pull terms out from under the radical, assuming real numbers.

$9$