Evaluate cube root of 36* cube root of 6

$\sqrt[3]{36} \cdot \sqrt[3]{6}$

Step 1

Combine using the product rule for radicals.

$\sqrt[3]{36 \cdot 6}$

Step 2

Write the expression using exponents.

Multiply $36$ by $6$ .

$\sqrt[3]{216}$

Rewrite $216$ as $6^{3}$ .

$\sqrt[3]{6^{3}}$

Pull terms out from under the radical, assuming real numbers.

$6$