Evaluate e^(- natural log of 2)

$e^{- \ln (2)}$

Simplify $- \ln (2)$ by moving $- 1$ inside the logarithm.

$e^{\ln (2^{- 1})}$

Exponentiation and log are inverse functions.

$2^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{2}$

Decimal Form:

$0.5$