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Evaluate e^(pii)+1

$e^{π i} + 1$

Simplify each term.

Reorder $π$ and $i$ .

$e^{i π} + 1$

Apply Euler\'s identity $e^{i π} = - 1$ .

$- 1 + 1$

$- 1 + 1$

Add $- 1$ and $1$ .

$0$

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