Evaluate f(2)=5x^2+10x-1

$f (2) = 5 x^{2} + 10 x - 1$

Step 1

Divide each term in $f (2) = 5 x^{2} + 10 x - 1$ by $2$ .

$\frac{f \cdot 2}{2} = \frac{5 x^{2}}{2} + \frac{10 x}{2} + \frac{- 1}{2}$

Step 2

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{f \cdot 2}{2} = \frac{5 x^{2}}{2} + \frac{10 x}{2} + \frac{- 1}{2}$

Divide $f$ by $1$ .

$f = \frac{5 x^{2}}{2} + \frac{10 x}{2} + \frac{- 1}{2}$

Step 3

Simplify the right side.

Simplify each term.

Cancel the common factor of $10$ and $2$ .

Factor $2$ out of $10 x$ .

$f = \frac{5 x^{2}}{2} + \frac{2 (5 x)}{2} + \frac{- 1}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$f = \frac{5 x^{2}}{2} + \frac{2 (5 x)}{2 (1)} + \frac{- 1}{2}$

Cancel the common factor.

$f = \frac{5 x^{2}}{2} + \frac{2 (5 x)}{2 \cdot 1} + \frac{- 1}{2}$

Rewrite the expression.

$f = \frac{5 x^{2}}{2} + \frac{5 x}{1} + \frac{- 1}{2}$

Divide $5 x$ by $1$ .

$f = \frac{5 x^{2}}{2} + 5 x + \frac{- 1}{2}$

Move the negative in front of the fraction.

$f = \frac{5 x^{2}}{2} + 5 x - \frac{1}{2}$