Evaluate f(x)=(1/3)^2

$f (x) = {(\frac{1}{3})}^{2}$

Simplify ${(\frac{1}{3})}^{2}$ .

Apply the product rule to $\frac{1}{3}$ .

$f (x) = \frac{1^{2}}{3^{2}}$

One to any power is one.

$f (x) = \frac{1}{3^{2}}$

Raise $3$ to the power of $2$ .

$f (x) = \frac{1}{9}$

Subtract $f (x)$ from both sides of the equation.

$0 = \frac{1}{9} - f (x)$

Rewrite the equation as $\frac{1}{9} - f (x) = 0$ .

$\frac{1}{9} - f (x) = 0$