Evaluate g(-x)=-x^3

$g (- x) = - x^{3}$

Step 1

Divide each term in $g (- x) = - x^{3}$ by $- 1 x$ .

$\frac{g (- x)}{- 1 x} = \frac{- x^{3}}{- 1 x}$

Step 2

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{g (x)}{x} = \frac{- x^{3}}{- 1 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{g x}{x} = \frac{- x^{3}}{- 1 x}$

Divide $g$ by $1$ .

$g = \frac{- x^{3}}{- 1 x}$

Step 3

Simplify the right side.

Dividing two negative values results in a positive value.

$g = \frac{x^{3}}{x}$

Cancel the common factor of $x^{3}$ and $x$ .

Factor $x$ out of $x^{3}$ .

$g = \frac{x \cdot x^{2}}{x}$

Cancel the common factors.

Raise $x$ to the power of $1$ .

$g = \frac{x \cdot x^{2}}{x^{1}}$

Factor $x$ out of $x^{1}$ .

$g = \frac{x \cdot x^{2}}{x \cdot 1}$

Cancel the common factor.

$g = \frac{x \cdot x^{2}}{x \cdot 1}$

Rewrite the expression.

$g = \frac{x^{2}}{1}$

Divide $x^{2}$ by $1$ .

$g = x^{2}$