Evaluate k(t)=10t-19

$k (t) = 10 t - 19$

Step 1

Divide each term in $k t = 10 t - 19$ by $t$ .

$\frac{k t}{t} = \frac{10 t}{t} + \frac{- 19}{t}$

Step 2

Simplify the left side.

Cancel the common factor of $t$ .

Cancel the common factor.

$\frac{k t}{t} = \frac{10 t}{t} + \frac{- 19}{t}$

Divide $k$ by $1$ .

$k = \frac{10 t}{t} + \frac{- 19}{t}$

$k = \frac{10 t}{t} + \frac{- 19}{t}$

$k = \frac{10 t}{t} + \frac{- 19}{t}$

Step 3

Simplify the right side.

Simplify each term.

Cancel the common factor of $t$ .

Cancel the common factor.

$k = \frac{10 t}{t} + \frac{- 19}{t}$

Divide $10$ by $1$ .

$k = 10 + \frac{- 19}{t}$

$k = 10 + \frac{- 19}{t}$

Move the negative in front of the fraction.

$k = 10 - \frac{19}{t}$

$k = 10 - \frac{19}{t}$

$k = 10 - \frac{19}{t}$

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