Evaluate log base 4 of 2+ log base 4 of 32

$\log_{4} (2) + \log_{4} (32)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{4} (2 \cdot 32)$

Step 2

Multiply $2$ by $32$ .

$\log_{4} (64)$

Step 3

Logarithm base $4$ of $64$ is $3$ .

$3$