Evaluate log base 5 of 49* log base 8 of 5* log base 9 of 8* log base 7 of 9

$\log_{5} (49) \cdot \log_{8} (5) \cdot \log_{9} (8) \cdot \log_{7} (9)$

Multiply $\log_{5} (49) \log_{8} (5) \log_{9} (8)$ by $\log_{7} (9)$ .

$\log_{5} (49) \log_{8} (5) \log_{9} (8) \log_{7} (9)$

Rewrite $\log_{5} (49)$ using the change of base formula.

The change of base rule can be used if $a$ and $b$ are greater than $0$ and not equal to $1$ , and $x$ is greater than $0$ .

$\log_{a} (x) = \frac{\log_{b} (x)}{\log_{b} (a)} \log_{8} (5) \log_{9} (8) \log_{7} (9)$

Substitute in values for the variables in the change of base formula, using $b = 10$ .

$\frac{\log (49)}{\log (5)} \log_{8} (5) \log_{9} (8) \log_{7} (9)$

Rewrite $\log_{8} (5)$ using the change of base formula.

The change of base rule can be used if $a$ and $b$ are greater than $0$ and not equal to $1$ , and $x$ is greater than $0$ .

$\frac{\log (49)}{\log (5)} \log_{a} (x) = \frac{\log_{b} (x)}{\log_{b} (a)} \log_{9} (8) \log_{7} (9)$

Substitute in values for the variables in the change of base formula, using $b = 10$ .

$\frac{\log (49)}{\log (5)} \cdot \frac{\log (5)}{\log (8)} \log_{9} (8) \log_{7} (9)$

Cancel the common factor of $\log (5)$ .

Cancel the common factor.

$\frac{\log (49)}{\log (5)} \cdot \frac{\log (5)}{\log (8)} \log_{9} (8) \log_{7} (9)$

Rewrite the expression.

$\log (49) \frac{1}{\log (8)} \log_{9} (8) \log_{7} (9)$

Combine $\log (49)$ and $\frac{1}{\log (8)}$ .

$\frac{\log (49)}{\log (8)} \log_{9} (8) \log_{7} (9)$

Rewrite $\log_{9} (8)$ using the change of base formula.

The change of base rule can be used if $a$ and $b$ are greater than $0$ and not equal to $1$ , and $x$ is greater than $0$ .

$\frac{\log (49)}{\log (8)} \log_{a} (x) = \frac{\log_{b} (x)}{\log_{b} (a)} \log_{7} (9)$

Substitute in values for the variables in the change of base formula, using $b = 10$ .

$\frac{\log (49)}{\log (8)} \cdot \frac{\log (8)}{\log (9)} \log_{7} (9)$

Cancel the common factor of $\log (8)$ .

Cancel the common factor.

$\frac{\log (49)}{\log (8)} \cdot \frac{\log (8)}{\log (9)} \log_{7} (9)$

Rewrite the expression.

$\log (49) \frac{1}{\log (9)} \log_{7} (9)$

Combine $\log (49)$ and $\frac{1}{\log (9)}$ .

$\frac{\log (49)}{\log (9)} \log_{7} (9)$

Rewrite $\log (49)$ as $\log (7^{2})$ .

$\frac{\log (7^{2})}{\log (9)} \log_{7} (9)$

Expand $\log (7^{2})$ by moving $2$ outside the logarithm.

$\frac{2 \log (7)}{\log (9)} \log_{7} (9)$

Rewrite $\log (9)$ as $\log (3^{2})$ .

$\frac{2 \log (7)}{\log (3^{2})} \log_{7} (9)$

Expand $\log (3^{2})$ by moving $2$ outside the logarithm.

$\frac{2 \log (7)}{2 \log (3)} \log_{7} (9)$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \log (7)}{2 \log (3)} \log_{7} (9)$

Rewrite the expression.

$\frac{\log (7)}{\log (3)} \log_{7} (9)$

Rewrite $\log_{7} (9)$ using the change of base formula.

The change of base rule can be used if $a$ and $b$ are greater than $0$ and not equal to $1$ , and $x$ is greater than $0$ .

$\frac{\log (7)}{\log (3)} \log_{a} (x) = \frac{\log_{b} (x)}{\log_{b} (a)}$

Substitute in values for the variables in the change of base formula, using $b = 10$ .

$\frac{\log (7)}{\log (3)} \cdot \frac{\log (9)}{\log (7)}$

Cancel the common factor of $\log (7)$ .

Cancel the common factor.

$\frac{\log (7)}{\log (3)} \cdot \frac{\log (9)}{\log (7)}$

Rewrite the expression.

$\frac{1}{\log (3)} \log (9)$

Combine $\frac{1}{\log (3)}$ and $\log (9)$ .

$\frac{\log (9)}{\log (3)}$

Rewrite $\log (9)$ as $\log (3^{2})$ .

$\frac{\log (3^{2})}{\log (3)}$

Expand $\log (3^{2})$ by moving $2$ outside the logarithm.

$\frac{2 \log (3)}{\log (3)}$

Cancel the common factor of $\log (3)$ .

Cancel the common factor.

$\frac{2 \log (3)}{\log (3)}$

Divide $2$ by $1$ .

$2$

Evaluate log base 5 of 49* log base 8 of 5* log base 9 of 8* log base 7 of 9

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