Evaluate log base 5 of x- log base 5 of 25=7

Use the quotient property of logarithms, ${\displaystyle {\log }_b\left(x\right)-{\log }_b\left(y\right)={\log }_b\left(\frac{x}{y}\right)}$.

Rewrite ${\displaystyle {\log }_5\left(\frac{x}{25}\right)=7}$ in exponential form using the definition of a logarithm. If ${\displaystyle x}$ and ${\displaystyle b}$ are positive real numbers and ${\displaystyle b\ne 1}$, then ${\displaystyle {\log }_b\left(x\right)=y}$ is equivalent to ${\displaystyle b^y=x}$.