Evaluate log base 6 of 36+ log base 4 of 4+ log base 3 of 1/27

$\log_{6} (36) + \log_{4} (4) + \log_{3} (\frac{1}{27})$

Simplify each term.

Logarithm base $6$ of $36$ is $2$ .

$2 + \log_{4} (4) + \log_{3} (\frac{1}{27})$

Logarithm base $4$ of $4$ is $1$ .

$2 + 1 + \log_{3} (\frac{1}{27})$

Logarithm base $3$ of $\frac{1}{27}$ is $- 3$ .

$2 + 1 - 3$

Simplify by adding and subtracting.

Add $2$ and $1$ .

$3 - 3$

Subtract $3$ from $3$ .

$0$