Evaluate log of (10)^-8

$\log ({(10)}^{- 8})$

Use logarithm rules to move $- 8$ out of the exponent.

$- 8 \log (10)$

Logarithm base $10$ of $10$ is $1$ .

$- 8 \cdot 1$

Multiply $- 8$ by $1$ .

$- 8$

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