Evaluate natural log of 1/(e^12)

$\ln (\frac{1}{e^{12}})$

Move $e^{12}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\ln (e^{- 12})$

Expand $\ln (e^{- 12})$ by moving $- 12$ outside the logarithm.

$- 12 \ln (e)$

The natural logarithm of $e$ is $1$ .

$- 12 \cdot 1$

Multiply $- 12$ by $1$ .

$- 12$

Related Questions