Evaluate natural log of e^-6

$\ln (e^{- 6})$

Expand $\ln (e^{- 6})$ by moving $- 6$ outside the logarithm.

$- 6 \ln (e)$

The natural logarithm of $e$ is $1$ .

$- 6 \cdot 1$

Multiply $- 6$ by $1$ .

$- 6$

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