Evaluate natural log of e^(9x)

$\ln (e^{9 x})$

Use logarithm rules to move $9 x$ out of the exponent.

$9 x \ln (e)$

The natural logarithm of $e$ is $1$ .

$9 x \cdot 1$

Multiply $9$ by $1$ .

$9 x$

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