Evaluate natural log of e^e

$\ln (e^{e})$

Expand $\ln (e^{e})$ by moving $e$ outside the logarithm.

$e \ln (e)$

The natural logarithm of $e$ is $1$ .

$e \cdot 1$

Multiply $e$ by $1$ .

$e$

The result can be shown in multiple forms.

Exact Form:

$e$

Decimal Form:

$2.71828182 \dots$