Evaluate natural log of e square root of 6

$\ln (e \sqrt{6})$

Rewrite $\ln (e \sqrt{6})$ as $\ln (e) + \ln (\sqrt{6})$ .

$\ln (e) + \ln (\sqrt{6})$

The natural logarithm of $e$ is $1$ .

$1 + \ln (\sqrt{6})$

The result can be shown in multiple forms.

Exact Form:

$1 + \ln (\sqrt{6})$

Decimal Form:

$1.89587973 \dots$