Evaluate (p^-8)/(7^-2q^-9)

$\frac{p^{- 8}}{7^{- 2} q^{- 9}}$

Move $p^{- 8}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{7^{- 2} q^{- 9} p^{8}}$

Move $7^{- 2}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{7^{2}}{q^{- 9} p^{8}}$

Move $q^{- 9}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{7^{2} q^{9}}{p^{8}}$

Raise $7$ to the power of $2$ .

$\frac{49 q^{9}}{p^{8}}$