Evaluate sin(x)^2+cos(x)^2=1

$\sin^{2} (x) + \cos^{2} (x) = 1$

Step 1

Subtract $1$ from both sides of the equation.

$\sin^{2} (x) + \cos^{2} (x) - 1 = 0$

Step 2

Simplify $\sin^{2} (x) + \cos^{2} (x) - 1$ .

Apply pythagorean identity.

$1 - 1 = 0$

Subtract $1$ from $1$ .

$0 = 0$

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true

Step 4

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$

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