Evaluate sixth root of 2* square root of 2

$\sqrt[6]{2} \cdot \sqrt{2}$

Multiply $\sqrt[6]{2} \sqrt{2}$ .

Rewrite the expression using the least common index of $6$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\sqrt[6]{2} \cdot 2^{\frac{1}{2}}$

Rewrite $2^{\frac{1}{2}}$ as $2^{\frac{3}{6}}$ .

$\sqrt[6]{2} \cdot 2^{\frac{3}{6}}$

Rewrite $2^{\frac{3}{6}}$ as $\sqrt[6]{2^{3}}$ .

$\sqrt[6]{2} \sqrt[6]{2^{3}}$

Combine using the product rule for radicals.

$\sqrt[6]{2 \cdot 2^{3}}$

Multiply $2$ by $2^{3}$ by adding the exponents.

Multiply $2$ by $2^{3}$ .

Raise $2$ to the power of $1$ .

$\sqrt[6]{2^{1} \cdot 2^{3}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sqrt[6]{2^{1 + 3}}$

Add $1$ and $3$ .

$\sqrt[6]{2^{4}}$

Raise $2$ to the power of $4$ .

$\sqrt[6]{16}$

Rewrite $16$ as $4^{2}$ .

$\sqrt[6]{4^{2}}$

Rewrite $\sqrt[6]{4^{2}}$ as $\sqrt[3]{\sqrt{4^{2}}}$ .

$\sqrt[3]{\sqrt{4^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$\sqrt[3]{4}$

The result can be shown in multiple forms.

Exact Form:

$\sqrt[3]{4}$

Decimal Form:

$1.58740105 \dots$